Error for named {placeholder}.format()

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#1

Hello is possible create named placeholder for {placeholder}.format(placeholder=$ColumnName)?

$Type.Format_Code={0}{Type}{2}{3}{4}{5}{6}{7}{8}{9}

$Type.Format_Code.format($A.Size,Type=$Type.Type,$Mat.Code,$T.Code.Code,$S.Code,$C1.Code,$C2.Code,$C3.Code,$C4.Code,$C5.Code)
#2

Yes! I think the only thing you may need to change is that any placeholder=VALUE arguments inside the parentheses of .format() need to go after all the positional arguments (i.e. those without “=”).

The positional arguments will replace placeholders {0}, {1}, etc., and the named ones will replace the corresponding name.

#3

I see

txt1 = "My name is {fname}, I'm {age}".format(fname = "John", age = 36)

The formula grows and it becomes difficult to manage placeholders, I wanted to make my life easier with named indexes, so tonight is not my night.

#4

Try in new fresh Table
$A.A={S}
$A.A.format(S=$A.B)
Works correctly, I try in the summary table with >53000 records does not work. Mystic.